Find the equation of the linear function represented by the table below in slope-intercept form.
x y 1 6 2 8 3 10 4 12
Find the slope of the line by choosing any two points, and finding the change in y over the change in x.
(1,6) and (2,8) are two points on the line 8 - 6 ----- = slope of the line {change in y over the change in x} 2 - 1 slope = 2 {subtracted in numerator and denominator} Substitute the slope and one of the points into slope-intercept form to find the y-intercept. slope = 2 and (1,6) is a point y = mx + b {slope-intercept form} 6 = 2(1) + b {substitute x and y-coordinates, along with the slope, into slope-intercept form} 6 = 2 + b {muiltiplied 2 by 1} b = 4 {subtracted 2 from each side} y-intercept is 4 Substitute the slope and y-intercpet back into slope-intercept form. y = mx + b {slope-intercept form} y = 2x + 4 is the equation of the line {subsituted} Ask Algebra House
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