Find the equation of the linear function represented by the table below in slope-intercept form.
x y 1 6 2 9 3 12 4 15
Find the slope of the line, by choosing two points and subtracting the y-coordinates over the x-coordinates.
y2 - y1 ------- = slope x2 - x1 9 - 6 ------ = slope {change in y over change in x} 2 - 1 slope = 3 Choose one of the points and substitute, with the slope, into slope-intercept form. y = mx + b {slope-intercept form} m is the slope b is the y-intercept point is (1,6) and slope is 3 y = mx + b 6 = 3(1) + b {substituted 1 in for x, 6 in for y, and 3 in for m, into slope-intercept form} 6 = 3 + b {multiplied 3 by 1} b = 3 {subtracted 3 from each side} y-intercept = 3 f(x) = 3x + 3 is the linear function {substituted slope and y-intercept back into slope-intercept form} Ask Algebra House
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