Find the equation of the linear function represented by the table below in slope-intercept form. x y 1 -6 2 -10 3 -14 4 -18 To get the equation, first find the slope of the line by using any two points. Subtract the y-coordinates over the subtraction of the x-coordinates. {change in y over change in x}
(1,-6) and (2,-10) {the first two points, but any two points will work} -10 - (-6) ---------- = slope {change in y over change in x} 2 - 1 -4 --- = slope {subtracted in numerator and denominator} 1 slope = -4 Substitute the slope, along with one of the points, into slope-intercept form, y = mx + b, to find the y-intercept. (1,-6) and m = -4 {the first point and the slope} y = mx + b {slope-intercept form} -6 = -4(1) + b {substituted 1 in for x, -6 in for y, and -4 in for m} -6 = -4 + b {multiplied} b = -2 {added 4 to each side} y-intercept = -2 Substitute the slope and y-intercept back into slope-intercept form. y = mx + b {slope-intercept form} y = -4x - 2 Ask Algebra House
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