Find the 66th term of the arithmetic sequence 3, 13, 23, …..
This is an arithmetic sequence, where there is a common difference. In other words, you are adding the same thing each time you jump from number to number.
The first term is 3, and then you are adding 10 each time, until you hit the 66th term. So, start with 3, and add 10, 65 times. 3 + 10(65) {started with 3, and added 10, 65 times} = 3 + 650 {multiplied 10 by 65} = 653 {added} 653 is the 66th term. Ask Algebra House
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