One person's age is three times that of another. If the sum of their ages is 64 , find each person's age?
x = one person’s age
3x = other person’s age {one is three times the other} x + 3x = 64 {the sum of their ages is 64} 4x = 64 {combined like terms} x = 16 {divided each side by 4} 3x = 48 {substituted 16, in for x, into 3x} 16 and 48 are their ages Ask Algebra House
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