The length of a house is 3 times its width. The width of the house is f yards. If the perimeter of the house is h yards, express h in terms of f.
f = width {width of house is f yards}
3f = length {length is 3 times the width} Assuming the house is in the shape of a rectangle: Perimeter of a rectangle = 2(width) + 2(length) h = 2(f) + 2(3f) {substituted f in for width and 3f in for length} h = 2f + 6f {multiplied 2 by 3f} h = 8f yds {added} Ask Algebra House
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