Two planes just took off from Boston, MA. The first plane is traveling 3 times as fast as the second plane. After traveling in the same direction for 2 hours, they are 396 miles apart. What is the average speed of each plane? (Hint: Since they are traveling in the same direction, the distance between them will be the difference of their distances.)
distance = rate x time
d = rt first plane rate = 3r {three times the second plane’s rate} time = 2 {2 hours} d = 3r(2) {distance = rate x time} d = 6r {multiplied} second plane rate = r time = 2 {2 hours} d = 2r {distance = rate x time} 6r  2r = 396 {distance between them is difference in distances} 4r = 396 {combined like terms} r = 99 mph {second plane’s rate} 3r is the first plane’s rate {taken from above} 3r = 3(99) = 297 mph {first plane’s rate} first plane = 297 mph second plane = 99 mph Ask the House
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