Two cyclists, 90 km apart, start riding toward each other at the same time. One cycles twice as fast as the other. If they meet 2 hours later, at what average speed is each cyclist traveling?
distance = rate x time
d = rt one cyclist rate = r time = 2 {they meet in 2 hours} d = 2r {distance = rate x time} other cyclist rate = 2r {cycles twice as fast as first} time = 2 {they meet in 2 hours} d = 4r {distance = rate x time} When they meet, their combined distance is 90 km. 2r + 4r = 90 {added distances together and set equal to 90} 6r = 90 {combined like terms} r = 15 {divided each side by 6} 2r = 30 {substituted 15, in for r, into 2r} one cyclist is traveling 15 km per hour the other cyclist is traveling 30 km per hour Ask the House
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