Kevin leaves his bakery at 6.50 am to deliver some pastries to a hotel. If he drives at a constant speed of 80km/h, He will reach the hotel on time. If he drives at a constant speed of 64km/h, he will be 10mins late. At what time is Kevin supposed to deliver the pastries to the hotel?
distance = rate x time
at 80 km/hr d = 80t at 64 km/hr d = 64(t + 1/6) {time plus 10 minutes or 1/6 of an hour} 80t = 64(t + 1/6) {the distances are equal} 80t = 64t + 32/3 {used distributive property} 16t = 32/3 {subtracted 64t from each side} t = 2/3 {divided each side by 16} 2/3 of an hour is 40 minutes Add 40 minutes onto 6:50 am He is supposed to arrive at 7:30 Ask the House
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