Line kk has a slope of 5. Line jj is perpendicular to line kk and passes through the point (5,9).
Create the equation for line jj.
Perpendicular lines have slopes which are negative reciprocals.
The slope of line kk is 5. Therefore the slope of line jj would be 1/5. Slopeintercept form is y = mx + b m is the slope b is the yintercept Substitute the point (5,9) and the slope, 1/5, into slopeintercept form to get the yintercept. 9 = (1/5)(5) + b {substituted 9 in for y, 1/5 in for m, and 5 in for x} 9 = 1 + b {multiplied 1/5 by 5} b = 8 {subtracted 1 from each side} yintercept is 8 y = (1/5)x + 8 is the equation of the line {substituted 1/5 in for slope and 8 in for yintercept} Ask Algebra House
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