Three times the lesser of two consecutive even integers is 6 less than six times the greater number. Find the integer.
x = first even integer
x + 2 = second even integer 3x = 6(x + 2) - 6 {three times the lesser is six less than six times the greater} 3x = 6x + 12 - 6 {used distributive property} 3x = 6x + 6 {combined like terms} -3x = 6 {subtracted 6x from each side} x = -2 {divided each side by -3} x + 2 = 0 {substituted 0, in for x, into x + 2} -2 and 0 are the two even integers Assuming you are classifying 0 and -2 as even integers, it works. Ask the House
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