A rectangular auditorium seats 1170 people. The number of seats in each row exceeds the number of rows by 9. Find the number of seats in each row.
x = number of rows
x + 9 = number of seats in each row {number of seats in each row exceeds number of rows by 9} seats in an auditorium = number of seats in each row multiplied by the number of rows x(x + 9) = 1170 {total seats equals number of rows multiplied by the number of seats in each row} x² + 9x = 1170 {used distributive property} x² + 9x  1170 = 0 {subtracted 1170 from each side} (x + 39)(x  30) = 0 {factored into two binomials} x + 39 = 0 or x  30 = 0 {set each factor equal to zero} x = 39 or x = 30 {solved each equation for x} x = 30 { number of rows cannot be negative} x + 9 = 39 {substituted 30, in for x, into x + 9} 39 seats in each row Ask the House
0 Comments
Your comment will be posted after it is approved.
Leave a Reply. 
Latest Videos
Archives
June 2021
