Which of the following inequalities is represented by the shaded region of the graph below ?
A.) y ≤ x + 1 or y ≥ x  3
B.) y ≥ x + 1 or y ≤ x  3 C.) y ≤ x + 1 or y ≥ (3/2)x + 3 D,) y ≤ x + 1 or y ≤ (3/2)x  3 E.) y ≤ x + 1 or y ≥ (3/2)x  3
When graphing inequalities:
First, locate the yintercept of each line, while also determining the slope of each line. One line yintercept is 1 slope is 1 Equation is y = x + 1 Also, the shading is below that line, and it is a solid line, Therefore, the inequality is: y ≤ x + 1 {boundary line is y = x + 1, using ≤ sign because of solid line, using ≤ sign because of shading below} Other line yintercept is 3 slope is 3/2 Equation of boundary line is y = (3/2)x  3 Also, the shading is above that line, and it is a solid line. Therefore, the inequality is: y ≥ (3/2)x  3 {boundary line is y = (3/2)x  3, using ≥ sign because of solid line, using ≥ sign because of shading above} Put the two together, and you have: E.) y ≤ x + 1 or y ≥ (3/2)x  3 Ask Algebra House Comments are closed.

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