Which of the following inequalities is represented by the shaded region of the graph below ?
A.) y ≤ x + 1 or y ≥ x - 3
B.) y ≥ x + 1 or y ≤ x - 3 C.) y ≤ x + 1 or y ≥ (-3/2)x + 3 D,) y ≤ x + 1 or y ≤ (-3/2)x - 3 E.) y ≤ x + 1 or y ≥ (-3/2)x - 3
When graphing inequalities:
First, locate the y-intercept of each line, while also determining the slope of each line. One line y-intercept is 1 slope is 1 Equation is y = x + 1 Also, the shading is below that line, and it is a solid line, Therefore, the inequality is: y ≤ x + 1 {boundary line is y = x + 1, using ≤ sign because of solid line, using ≤ sign because of shading below} Other line y-intercept is -3 slope is -3/2 Equation of boundary line is y = (-3/2)x - 3 Also, the shading is above that line, and it is a solid line. Therefore, the inequality is: y ≥ (-3/2)x - 3 {boundary line is y = (-3/2)x - 3, using ≥ sign because of solid line, using ≥ sign because of shading above} Put the two together, and you have: E.) y ≤ x + 1 or y ≥ (-3/2)x - 3 Ask Algebra House Comments are closed.
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