When 5 consecutive integers are added together and the sum is then multiplied by 5, the result is 225. Which of
the following is the fourth of the 5 consecutive integers? A.) 5 B.) 7 C.) 10 D.) 11 E.) 13
x = first consecutive integer
x + 1 = second consecutive integer x + 2 = third consecutive integer x + 3 = fourth consecutive integer x + 4 = fifth consecutive integer 5(x + x + 1 + x + 2 + x + 3 + x + 4) = 225 {the sum of the five consecutive integers is multiplied by 5} 5(5x + 10) = 225 {combined like terms} 25x + 50 = 225 {used distributive property} 25x = 175 {subtracted 50 from each side} x = 7 {divided each side by 25} x + 3 = 10 {substituted 7, in for x, into x + 3, the fourth consecutive integer} 10 is the fourth consecutive integer Ask Algebra House Comments are closed.

Latest Videos
Archives
December 2023
ACT is a registered trademark of ACT, Inc. SAT is a registered trademark of the College Board. ACT and SAT are not affiliated with this site.
