You can find the volume of an irregularly shaped solid object by completely submerging it in water and calculating the volume of water the object displaces. You completely submerge a solid object in a rectangular tank that has a base of 40 centimeters by 30 centimeters and is filled with water to a depth of 20 centimeters. The object sinks to the bottom, and the water level goes up 0.25 centimeters. What is the volume, in cubic centimeters, of the object?

A.,) 300

B.) 240

C.) 200

D.) 150

E.) 75

A.,) 300

B.) 240

C.) 200

D.) 150

E.) 75

The volume of the water displaced, in the rectangular tank, is

V = 40(30)(0.25) {dimensions of tank are 40x30 and the height of the displaced water is 0.25}

= 300 cm³ {multiplied and labeled in cubic centimeters for volume}

**V = lwh**{volume = length x width x height}V = 40(30)(0.25) {dimensions of tank are 40x30 and the height of the displaced water is 0.25}

= 300 cm³ {multiplied and labeled in cubic centimeters for volume}

**A.) 300**

*Ask Algebra House*