What is the slope of the line given by the equation:
14x  11y + 16 = 0 A.) 11 B.) 14/11 C.) 11/14 D.) 14/11 E.) 14
Slopeintercept form is y = mx + b
m is the slope {coefficient of x} b is the yintercept {where the line crosses the yaxis} Get the equation in slopeintercept form. 14x  11y + 16 = 0 +11y +11y 11y = 14x + 16 {added 11y to each side} y = (14/11)x + (16/11) {divided each side by 11} slope = 14/11 D.) 14/11 Ask Algebra House Comments are closed.

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