A.) 2y + 3x = -3

B.) y + 3x = 2

C.) 2y - x = 6

D.) y - 2x = 4

E.) 2y + x = 6

**Slope-intercept form for the equation of a line is y = mx + b**

**m is the slope**

**b is the y-intercept**

**Perpendicular lines have slopes which are negative reciprocals.**

Find the slope of the given line.

4x - 2y = 6

-2y = -4x + 6 {subtracted 4x from each side}

y = 2x - 3 {divided each side by -2}

slope = 2

Perpendicular slope is -1/2 {perpendicular lines have slopes which are negative reciprocals}

y-intercept is 3 {given}

y = (-1/2)x + 3 {substituted slope and y-intercept, of new line, into slope-intercept form}

2y = -x + 6 {multiplied entire equation by 2, to eliminate fraction}

2y + x = 6 {subtracted x from each side to get equation into standard form, Ax + By = C}

**C.) 2y - x = 6**