If x is a real number such that x³ = 64, then x² + √x = ?

A.) 4

B.) 10

C.) 18

D.) 20

E.) 47

A.) 4

B.) 10

C.) 18

D.) 20

E.) 47

If x³ = 64

x = 4 {took the cube root of each side}

Since x = 4,

then x² + √x

= 4² + √4 {substituted 4 in for x}

= 16 + 2 {evaluated exponent and square root}

= 18 {added}

x = 4 {took the cube root of each side}

Since x = 4,

then x² + √x

= 4² + √4 {substituted 4 in for x}

= 16 + 2 {evaluated exponent and square root}

= 18 {added}

**C.) 18****Ask Algebra House**