Let the function f(a,b) be defined as f(a,b) = b² - a.
For all x and y, f((x² + y²),(x - y)) = ? A.) 2y² B.) 0 C.) -2y² D.) -2xy + 2y² E.) -2xy
Substitute (x² + y²) in for a, and (x - y) in for b, into b² - a.
f(a,b) = b² - a f((x² + y²), (x - y) = (x - y)² - (x² + y²) {substituted (x² - y²) for a and (x - y) for b into b² - a} = (x - y)(x - y) - x² - y² {squared the binomial and removed parentheses on second binomial, distributing negative sign} = x² - 2xy + y² - x² - y² {used distributive property / FOIL method} = -2xy {combined like terms} E.) -2xy Ask Algebra House Comments are closed.
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