Let the function f(a,b) be defined as f(a,b) = b²  a.
For all x and y, f((x² + y²),(x  y)) = ? A.) 2y² B.) 0 C.) 2y² D.) 2xy + 2y² E.) 2xy
Substitute (x² + y²) in for a, and (x  y) in for b, into b²  a.
f(a,b) = b²  a f((x² + y²), (x  y) = (x  y)²  (x² + y²) {substituted (x²  y²) for a and (x  y) for b into b²  a} = (x  y)(x  y)  x²  y² {squared the binomial and removed parentheses on second binomial, distributing negative sign} = x²  2xy + y²  x²  y² {used distributive property / FOIL method} = 2xy {combined like terms} E.) 2xy Ask Algebra House Comments are closed.

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