If x = 4 and y = 5, find the difference of y³  3x and x³  3y. A.) 5 B.) 25 C.) 64 D.) 34 E.) 27 y³  3x  (x³  3y) {subtracting} = y³  3x  x³ + 3y {distributed negative sign through parentheses} = (5)³  3(4)  (4)³ + 3(5) {substituted 4 in for x and 5 in for y} = 125  12  64 + 15 {evaluated exponents and multiplied} = 64 {added and subtracted from left to right} C.) 64  Algebra House
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