The Johnsons can afford 220 feet of fencing material. They want to fence in a rectangular area with a length 20 feet more than twice the width. What will the dimension be? A.) 40 ft x 80 ft B.) 45 ft x 110 ft C.) 30 ft x 80 ft D.) 100 ft x 25 ft E.) 50 ft x 60 ft w = width 2w + 20 = length Perimeter of a rectangle is 2(width) + 2(length) 2w + 2(2w + 20) = 220 {perimeter is 2(width) + 2(length)} 2w + 4w + 40 = 20 {used distributive property} 6w + 40 = 220 {combined like terms} 6w = 180 {subtracted 40 from both sides} w = 30 {divided both sides by 6} 2w + 20 = 80 {substituted 30, in for w, into 2w + 20} width = 30 ft length = 80 ft C.) 30 ft x 80 ft - Algebra House
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