The Johnsons can afford 220 feet of fencing material. They want to fence in a rectangular area with a length 20 feet more than twice the width. What will the dimension be?

A.) 40 ft x 80 ft

B.) 45 ft x 110 ft

C.) 30 ft x 80 ft

D.) 100 ft x 25 ft

E.) 50 ft x 60 ft

A.) 40 ft x 80 ft

B.) 45 ft x 110 ft

C.) 30 ft x 80 ft

D.) 100 ft x 25 ft

E.) 50 ft x 60 ft

w = width

2w + 20 = length

Perimeter of a rectangle is 2(width) + 2(length)

2w + 2(2w + 20) = 220 {perimeter is 2(width) + 2(length)}

2w + 4w + 40 = 20 {used distributive property}

6w + 40 = 220 {combined like terms}

6w = 180 {subtracted 40 from both sides}

w = 30 {divided both sides by 6}

2w + 20 = 80 {substituted 30, in for w, into 2w + 20}

width = 30 ft

length = 80 ft

C.) 30 ft x 80 ft

**- Algebra House**