Line k has a slope of -5. Line j is perpendicular to line k, and passes through the point (5,9). Create the equation for line j.

**Perpendicular lines have slopes which are negative reciprocals.**

Slope of line k is -5, therefore slope of line j is 1/5.

**Slope-intercept form is y = mx + b**

m is the slope

b is the y-intercept

m is the slope

b is the y-intercept

Line j slope is 1/5 and passes through the point (5,9).

Find the y-intercept of line j by substituting point and slope into slope-intercept form

y = mx + b

9 = (1/5)(5) + b {substituted point for x and y, and slope into slope-intercept form}

9 = 1 + b {multiplied 1/5 by 5}

b = 8 {subtracted 1 from each side}

**y = (1/5)x + 8**

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