Line k has a slope of 5. Line j is perpendicular to line k, and passes through the point (5,9). Create the equation for line j.
Perpendicular lines have slopes which are negative reciprocals.
Slope of line k is 5, therefore slope of line j is 1/5. Slopeintercept form is y = mx + b m is the slope b is the yintercept Line j slope is 1/5 and passes through the point (5,9). Find the yintercept of line j by substituting point and slope into slopeintercept form y = mx + b 9 = (1/5)(5) + b {substituted point for x and y, and slope into slopeintercept form} 9 = 1 + b {multiplied 1/5 by 5} b = 8 {subtracted 1 from each side} y = (1/5)x + 8 Ask Algebra House Comments are closed.

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