Create the equation of a line that is perpendicular to 2y = 14 + (2/3)x and passes through the point (2,8).
Perpendicular lines have slopes which are negative reciprocals.
Slopeintercept form is y = mx + b m is the slope b is the yintercept Find the slope of the given line, then take the negative reciprocal to get the slope of the new line. 2y = 14 + (2/3)x y = (1/3)x + 7 {divided each side by 2 and rearranged to be in slopeintercept form} slope = 1/3 {slope is the number in front of the x, when in slopeintercept form} Perpendicular slope = 3 {took negative reciprocal of 1/3} Use slope intercept form to get the equation of the line with a slope of 3 and passing through (2,8). slope is 3 and point is (2,8) y = mx + b {slopeintercept form} 8 = 3(2) + b {substituted point and slope into slopeintercept form} 8 = 6 + b {multiplied} b = 2 {subtracted 2/3 from each side} y = 3x + 2 {substituted slope and yintercept into slopeintercept form} Ask Algebra House Comments are closed.

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