A total of 300 children and adults attended a school play. There were 21 times as many children in attendance as there
were adults. This situation is modeled by the given system of equations, where a represents the number of adults and c represents the number of children. c = 21a a + c = 330 How many children attended the play?
Use the given system of equations to solve for c, the number of children attending.
c = 21a a + c = 330 a + 21a = 330 {substituted 21a, in for c, into second equation} 22a = 330 {combined like terms} a = 15 {divided each side by 22} 15 adults attended c = 21a {first original equation} c = 21(15) {substituted 15, in for a, into first equation} c = 315 {multiplied} 315 children attended Ask Algebra House Comments are closed.

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