An equation is shown.
2x²  5x  3 = 0 What value of x makes the equation true?
Factor the quadratic expression into two binomials, by grouping.
2x²  5x  3 = 0 2x²  6x + x  3 = 0 {split 5x, into two terms whose coefficients multiply to get 2(3) and add to get 5} 2x(x  3) + 1(x  3) = 0 {factored 2x out of first two terms and 1 out of last two terms} (2x + 1)(x  3) = 0 {factored (x  3) out of the two terms} 2x + 1 = 0 or x  3 = 0 {set each factor equal to zero} 2x = 1 or x = 3 {subtracted 1 from each side of first equation and added 3 to each side of second equation} x = 1/2 or x = 3 {divided first equation by 2} The xintercepts of the parabola formed representing the function f(x) = 2x²  5x  3 are 1/2 and 3. Comments are closed.

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