A system of equations is given
y + 2 = 3(x - 1) y = -2x + 10 What is the solution to the system?
When finding the solution to a linear system, such as this, you are finding the point of intersection of the two lines.
y + 2 = 3(x - 1) y = -2x + 10 Substituted (-2x + 10), in for y, into first equation. -2x + 10 + 2 = 3(x - 1) {substituted (-2x + 10), in for y, into first equation} -2x + 12 = 3x - 3 {combined like terms and used distributive property} 5x = 15 {added 2x and 3 to each side} x = 3 {divided each side by 5} Substitute 3, in for x, into second original equation. y = -2x + 10 {second original equation} y = -2(3) + 10 {substituted 3, in for x, into second original equation} y = -6 + 10 {multiplied -2 by 3} y = 4 {added} x = 3 and y = 4 (3,4) is the solution to the system. Therefore, (3,4) is the point of intersection of the two lines. Comments are closed.
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