The first four terms of an arithmetic sequence are given.

27, 32, 37, 42, ...

What is the 60th term of the sequence ?

27, 32, 37, 42, ...

What is the 60th term of the sequence ?

Starting with 27, you will be adding 5, fifty-nine times

60th term = 27 + (60 - 1)(5)

= 27 + (59)(5) {subtracted inside parentheses}

= 27 + 295 {multiplied 59 by 5}

= 322 {added}

60th term = 27 + (60 - 1)(5)

= 27 + (59)(5) {subtracted inside parentheses}

= 27 + 295 {multiplied 59 by 5}

= 322 {added}

**The 60th term is 322***Ask Algebra House*