Which correctly factored form of the function f(x) = 36x² + 15x  6 can be used to identify the zeros?
A.) f(x) = (4x  1)(3x + 2) B.) f(x) = (12x  2)(3x + 3) C.) f(x) = 3(4x  1)(3x + 2) D.) f(x) = 3(12x  2)(3x + 3)
Look for a common factor to factor out, first.
36x² + 15x  6 = 3(12x² + 5x  2) {factored 3 out} Factor the remaining quadratic trinomial by grouping. 12x² + 5x  2 = 12x² + 8x  3x  2 {split the 5x into two terms, whose coefficients multiply to get 12(2) and add to get 5} = 4x(3x + 2)  1(3x + 2) {factored 4x out of first two terms and 1 out of last two terms} = (4x  1)(3x + 2) {factored (3x + 2) out of the two terms} Don't forget the 3 that was factored out earlier. C.) f(x) = 3(4x  1)(3x + 2) Ask Algebra House Comments are closed.

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