An equation is given.
5y  2x = 5 Create an ordered pair that represents one point on the graph of the equation.
Solve the equation for y. Then substitute a value in for x to get a corresponding y value.
5y  2x = 5 5y = 2x + 5 {added 2x to each side} y = (2/5)x + 1 {divided each side by 5} Substitute any x value into y = (2/5)x + 1 If x = 5, y = (2/5)(5) + 1 {substituted 5 in for x} y = 2 + 1 {multiplied 2/5 by 5} y = 3 {added} x = 5 and y = 3 (5,3) is one point that is on the graph of the equation Ask Algebra House Comments are closed.

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