Write an equation in Slope-intercept form for the line that is perpendicular to the line y = 2x - 5 that passes through the given point (4,-2).

In the line y = 2x - 5,

the slope is 2.

The perpendicular slope is -1/2

(4,-2) , m = -1/2 {point and slope}

y - y1 = m(x - x1) {point-slope form}

y - (-2) = (-1/2)(x - 4) {substituted point and slope into point-slope form}

y + 2 = (-1/2)x + 2 {used distributive property}

the slope is 2.

The perpendicular slope is -1/2

(4,-2) , m = -1/2 {point and slope}

y - y1 = m(x - x1) {point-slope form}

y - (-2) = (-1/2)(x - 4) {substituted point and slope into point-slope form}

y + 2 = (-1/2)x + 2 {used distributive property}

**y = (-1/2)x**{subtracted 2 from each side}*- Algebra House*