What expression must be subtracted from 3a - 2b - c to get a difference of 4a - 3b?

A.) a - b + c

B.) -a + b - c

C.) 7a - 5b - c

D.) -7a + 5b + c

A.) a - b + c

B.) -a + b - c

C.) 7a - 5b - c

D.) -7a + 5b + c

**Similar to deciding what number must be subtracted from 7 to get a difference of 4, you could subtract 4 from 7 and find out it is 3.**

**In this one, subtract the difference of (4a - 3b) from (3a - 2b - c)**

(3a - 2b - c) - (4a - 3b) {subtracted}

= 3a - 2b - c - 4a + 3b {removed parentheses, distributing negative sign}

= -a + b - c {combined like terms}

**B.) -a + b - c**

**Proof:**(3a - 2b - c) - (-a + b - c) should equal (4a - 3b)

= 3a - 2b - c + a - b + c {removed parentheses, distributing negative sign}

= 4a - 3b {combined like terms}

*- Algebra House*