How do you find the x-intercept and y-intercept, of this line? 8x - 2y = 32 To find the x-intercept, put 0 in for y: 8x - 2y = 32 8x - 2(0) = 32 {substituted 0 in for y} 8x = 32 {multiplied 2 by 0} x = 4 {divided both sides by 8} x-intercept = 4 .....coordinates are (4,0) To find the y-intercept, put 0 in for x: 8x - 2y = 32 8(0) - 2y = 32 {substituted 0 in for x} -2y = 32 {multiplied 8 by 0} y = -16 {divided both sides by -2} y-intercept = -16.....coordinates are (0,-16) © Algebra House
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