If the length of a rectangle is 7 more than the width of the rectangle and the area is 60sq.ft, find the perimeter of the rectangle. x = width x + 7 = length{length is 7 more than width} x(x + 7) = 60 {area of a rectangle is width x length} x² + 7x = 60 {used distributive property} x² + 7x  60 = 0 {subtracted 60 from both sides} (x + 12)(x  5) = 0 {factored into two binomials} x + 12 = 0 or x  5 = 0 {set each factor equal to 0} x = 12 or x = 5 {subtracted 12 and added 5 respectively} x = 5 {width of a rectangle cannot be negative} x + 7 = 12 {substituted 5, in for x, into x + 7} width = 5 ft and length = 12 ft Perimeter of a rectangle = 2(width) + 2(length) = 2(5) + 2(12) {substituted width and length into perimeter formula} = 10 + 24 {multiplied} Perimeter = 34 ft {added 10 and 24}
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