What is the vertex of the parabola y = x² + 8x + 5 ? y = x² + 8x + 5 a = 1, b = 8, and c = 5 {in standard form} b  is the xcoordinate of the vertex 2a 8  = xcoordinate of vertex {substituted 1 for a and 8 for b} 2(1) xcoordinate of vertex is 4 {simplified} y = x² + 8x + 5 {the equation of the parabola} y = (4)² + 8(4) + 5 {substituted 4 for x into equation to find ycoordinate of vertex} y = 16  32 + 5 {evaluated exponent and multiplied} y = 11 {added and subtracted} (4 , 11) is the vertex of the parabola  Algebra House
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