What is the vertex of the parabola y = x² + 8x + 5 ? y = x² + 8x + 5 a = 1, b = 8, and c = 5 {in standard form} -b ---- is the x-coordinate of the vertex 2a -8 ------ = x-coordinate of vertex {substituted 1 for a and 8 for b} 2(1) x-coordinate of vertex is -4 {simplified} y = x² + 8x + 5 {the equation of the parabola} y = (-4)² + 8(-4) + 5 {substituted -4 for x into equation to find y-coordinate of vertex} y = 16 - 32 + 5 {evaluated exponent and multiplied} y = -11 {added and subtracted} (-4 , -11) is the vertex of the parabola - Algebra House
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