How do you solve for n when 27^n=9^4? 27^n = 9^4 3^3n = 3^2(4) {changed both to have a base of 3....27 is 3³ and 9 is 3²} 3^3n = 3^8 {multiplied 2 by 4} 3n = 8 {since bases are equal, set the exponents equal to each other} n = 8/3 {divided both sides by 3} © Algebra House
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