How do you solve this for x: 3x/2 + 9/5 = 12 10[3x/2 + 9/5 = 12] {multiplied entire equation by least common denominator, 10} 10(3x/2) + 10(9/5) = 10(12) {multiplied each term by 10} 15x + 18 = 120 {cancelled and multiplied what's left} 15x = 102 {subtracted 18 from both sides} x = 102/15 {divided both sides by 15} x = 34/5 {reduced} © Algebra House
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