How do you solve this for x:

3x/2 + 9/5 = 12

3x/2 + 9/5 = 12

10[3x/2 + 9/5 = 12] {multiplied entire equation by least common denominator, 10}

10(3x/2) + 10(9/5) = 10(12) {multiplied each term by 10}

15x + 18 = 120 {cancelled and multiplied what's left}

15x = 102 {subtracted 18 from both sides}

x = 102/15 {divided both sides by 15}

**x = 34/5**{reduced}

*© Algebra House*