How do you solve this for x:
3x/2 + 9/5 = 12
3x/2 + 9/5 = 12
10[3x/2 + 9/5 = 12] {multiplied entire equation by least common denominator, 10}
10(3x/2) + 10(9/5) = 10(12) {multiplied each term by 10}
15x + 18 = 120 {cancelled and multiplied what's left}
15x = 102 {subtracted 18 from both sides}
x = 102/15 {divided both sides by 15}
x = 34/5 {reduced}
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