How do you solve this? 3  (x + 2)² = 7  x² 3  (x + 2)(x + 2) = 7  x² {when squaring a binomial, multiply it by itself} 3  (x² + 4x + 4 = 7  x² {used foil method} 3  x²  4x  4 = 7  x² {took out parentheses} x²  4x  1 = 7  x² {combined like terms} 4x  1 = 7 {added x² to both sides} 4x = 8 {added 1 to both sides} x = 2 {divided both sides by 4} © Algebra House
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