How do you solve this radical equation?y
y - √(y - 10) = 12
y - √(y - 10) = 12
-√(y - 10) = -y + 12 {subtracted y from both sides}
√(y - 10) = y - 12 {divided both sides by -1}
y - 10 = y² - 24y + 144 {squared both sides}
y² - 25y + 154 = 0 {subtracted y and added 10 to both sides}
(y - 14)(y - 11) = 0 {factored into two binomials}
y - 14 = 0 or y - 11 = 0 {set each factor equal to 0}
y = 14 or y = 11 {solved each equation for y}
y = 11 does not check if you put it back in
y = 14
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