How do you solve this radical equation?y y - √(y - 10) = 12 -√(y - 10) = -y + 12 {subtracted y from both sides} √(y - 10) = y - 12 {divided both sides by -1} y - 10 = y² - 24y + 144 {squared both sides} y² - 25y + 154 = 0 {subtracted y and added 10 to both sides} (y - 14)(y - 11) = 0 {factored into two binomials} y - 14 = 0 or y - 11 = 0 {set each factor equal to 0} y = 14 or y = 11 {solved each equation for y} y = 11 does not check if you put it back in y = 14 © Algebra House
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