How do you solve this radical equation?y y  √(y  10) = 12 √(y  10) = y + 12 {subtracted y from both sides} √(y  10) = y  12 {divided both sides by 1} y  10 = y²  24y + 144 {squared both sides} y²  25y + 154 = 0 {subtracted y and added 10 to both sides} (y  14)(y  11) = 0 {factored into two binomials} y  14 = 0 or y  11 = 0 {set each factor equal to 0} y = 14 or y = 11 {solved each equation for y} y = 11 does not check if you put it back in y = 14 © Algebra House
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