How would you add these two fractions? 3a/(a2b) + 6b/(2ba) 3a/(a2b) + 6b/(2ba)
= 3a/(a  2b) + 6b/(a + 2b) {flipped the 2nd denominator} =3a/(a  2b)  6b/(a  2b) {multiplied top and bottom of 2nd fraction by 1} notice, you now have a common denominator 3a  6b {combined like terms in numerators} a  2b 3(a  2b)  {factored 3 out of top} a  2b = 3 {cancelled (a  2b) on top and bottom}  Algebra House
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