How do you find the square root of 4y² over x? I tried finding the square root

of 4y² but then got stuck on the finding the square root of x.

of 4y² but then got stuck on the finding the square root of x.

√(4y²/x)

√4y²

----- {split into square root of numerator over square root of denominator}

√x

2y

--- {evaluated the square root of 4y²}

√x

2y √x

-------- {rationalized the denominator by multiplying top and bottom by the square root of x}

√x √x

2y√x

------- {multiplied in the denominator}

√x²

**2y √x**

--------{evaluated the square root of x²}

--------

**x**

- For an expression to be completely simplified, you cannot be left with a square root sign in the denominator. That is the purpose of rationalizing the denominator.

*- Algebra House*