How do you find the square root of 4y² over x? I tried finding the square root
of 4y² but then got stuck on the finding the square root of x.
of 4y² but then got stuck on the finding the square root of x.
√(4y²/x)
√4y²
----- {split into square root of numerator over square root of denominator}
√x
2y
--- {evaluated the square root of 4y²}
√x
2y √x
-------- {rationalized the denominator by multiplying top and bottom by the square root of x}
√x √x
2y√x
------- {multiplied in the denominator}
√x²
2y √x
-------- {evaluated the square root of x²}
x
- For an expression to be completely simplified, you cannot be left with a square root sign in the denominator. That is the purpose of rationalizing the denominator.
- Algebra House
