How do you find the square root of 4y² over x? I tried finding the square root of 4y² but then got stuck on the finding the square root of x. √(4y²/x) √4y²  {split into square root of numerator over square root of denominator} √x 2y  {evaluated the square root of 4y²} √x 2y √x  {rationalized the denominator by multiplying top and bottom by the square root of x} √x √x 2y√x  {multiplied in the denominator} √x² 2y √x  {evaluated the square root of x²} x  For an expression to be completely simplified, you cannot be left with a square root sign in the denominator. That is the purpose of rationalizing the denominator.  Algebra House
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