How would you simplify this? ³√(x^9 / 3y)
³√(x^9 / 3y) ³√x^9  {took cube root of numerator over cube root of denominator} ³√3y x³  {evaluated cube root of x^9 to be x³ on top} ³√3y x³ ³√9y²  {multiplied top and bottom by ³√9y², to eliminate radical in denominator} ³√3y ³√9y² x³ ³√9y²  {multiplied in denominator} ³√27y³ x³ ³√9y²  {evaluated cube root of 27y³ in denominator} 3y © Algebra House
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