How would you solve this for w?

3√(w + 1) = 6

3√(w + 1) = 6

3√(w + 1) = 6

√(w + 1) = 2 {divided both sides by 3}

w + 1 = 4 {squared both sides}

w = 3 {subtracted 1 from both sides}

- Algebra House

√(w + 1) = 2 {divided both sides by 3}

w + 1 = 4 {squared both sides}

w = 3 {subtracted 1 from both sides}

- Algebra House