Find the length of LO if 6x - 2 = LM, MO = 10, and LO = 11X - 7 LO is a straight line:
6x - 2 + 10 = 11x - 7 {LM + MO = LO} 6x + 8 = 11x - 7 {combined like terms} 8 = 5x - 7 {subtracted 6x from both sides} 15 = 5x {added 7 to both sides} x = 3 {divided both sides by 5} LO = 6x - 2 = 6(3) - 2 {substituted 3, in for x, into 6x - 2} = 18 - 2 {multiplied 6 by 3} LO = 16 {subtracted} © Algebra House
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