Find the length of LO if 6x - 2 = LM, MO = 10, and LO = 11X - 7
LO is a straight line:
6x - 2 + 10 = 11x - 7 {LM + MO = LO}
6x + 8 = 11x - 7 {combined like terms}
8 = 5x - 7 {subtracted 6x from both sides}
15 = 5x {added 7 to both sides}
x = 3 {divided both sides by 5}
LO = 6x - 2
= 6(3) - 2 {substituted 3, in for x, into 6x - 2}
= 18 - 2 {multiplied 6 by 3}
LO = 16 {subtracted}
© Algebra House
6x - 2 + 10 = 11x - 7 {LM + MO = LO}
6x + 8 = 11x - 7 {combined like terms}
8 = 5x - 7 {subtracted 6x from both sides}
15 = 5x {added 7 to both sides}
x = 3 {divided both sides by 5}
LO = 6x - 2
= 6(3) - 2 {substituted 3, in for x, into 6x - 2}
= 18 - 2 {multiplied 6 by 3}
LO = 16 {subtracted}
© Algebra House
