The distance, s (in feet), that an object on the moon will fall in the seconds is given by s(t) = 2.735t². How far will an object fall on the moon in 3 seconds? If t = 3 seconds
s(t) = 2.735t² s(3) = 2.735(3)² {substituted 3 for t} = 2.735(9) {evaluated exponent} = 24.615 ft {multiplied} Ask Algebra House Comments are closed.

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