How do you cube this binomial?

How do you cube this binomial:  (3x + 4)³ ?

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(3x + 4)³   {you have to multiply (3x + 4) by itself three times}
= (3x + 4)(3x + 4)(3x + 4)   {multiplying the binomial by itself three times}
= (9x² + 24x + 16)(3x + 4)   {used foil method on first two binomials}
= 27x³ + 72x² + 48x + 36x² + 96x + 64   {used distributive property}
= 27x³ + 108x² + 144x + 64   {combined like terms}

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