How do you cube this binomial?

(3x + 4)³

(3x + 4)³ {you have to multiply 3x + 4 by itself three times}
= (3x + 4)(3x + 4)(3x + 4) {multiplying the binomial by itself three times}
= (9x² + 24x + 16)(3x + 4) {used foil method on first two binomials}
= 27x³ + 72x² + 48x + 36x² + 96x + 64 {used distributive property}
= 27x³ + 108x² + 144x + 64 {combined like terms}

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