In the standard (x,y) coordinate plane, what is the slope of the line 11x + 6y = 3?
Slope-intercept form is y = mx + b
m is the slope
b is the y-intercept
11x + 6y = 3
6y = -11x + 3 {subtracted 11x from each side}
y = (-11/6)x + (1/2) {divided each side by 6}
slope = -11/6
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m is the slope
b is the y-intercept
11x + 6y = 3
6y = -11x + 3 {subtracted 11x from each side}
y = (-11/6)x + (1/2) {divided each side by 6}
slope = -11/6
Ask Algebra House
