In the standard (x,y) coordinate plane, what is the slope of the line 11x + 6y = 3?
Slope-intercept form is y = mx + b
m is the slope b is the y-intercept 11x + 6y = 3 6y = -11x + 3 {subtracted 11x from each side} y = (-11/6)x + (1/2) {divided each side by 6} slope = -11/6 Ask Algebra House Comments are closed.
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