In the standard (x,y) coordinate plane, what is the slope of the line 11x + 6y = 3?

**Slope-intercept form is y = mx + b**

m is the slope

b is the y-intercept

m is the slope

b is the y-intercept

11x + 6y = 3

6y = -11x + 3 {subtracted 11x from each side}

y = (-11/6)x + (1/2) {divided each side by 6}

**slope = -11/6**

**- Algebra House**