The sum of three numbers is 62 . The first number is 10 more than the second. The third number is 2 times the first. What are the numbers?

x = the second number

x + 10 = the first number

2(x + 10) = the third number

x + x + 10 + 2(x + 10) = 62 {sum of the three numbers is 62}

x + x + 10 + 2x + 20 = 62 {used distributive property}

4x + 30 = 62 {combined like terms}

4x = 32 {subtracted 30 from each side}

x = 8 {divided each side by 4}

x + 10 = 18 {substituted 8, in for x, into x + 10}

2(x + 10) = 36 {substituted 8, in for x, into 2(x + 10)}

x + 10 = the first number

2(x + 10) = the third number

x + x + 10 + 2(x + 10) = 62 {sum of the three numbers is 62}

x + x + 10 + 2x + 20 = 62 {used distributive property}

4x + 30 = 62 {combined like terms}

4x = 32 {subtracted 30 from each side}

x = 8 {divided each side by 4}

x + 10 = 18 {substituted 8, in for x, into x + 10}

2(x + 10) = 36 {substituted 8, in for x, into 2(x + 10)}

**first number is 18**

second number is 8

third number is 36

- Algebra Housesecond number is 8

third number is 36

- Algebra House