Find the equation of the line perpendicular to y = 4x  5 and passing through (1,5) .
Perpendicular lines have slopes which are negative reciprocals.
Slopeintercept form is y = mx + b m is the slope b is the yintercept In y = 4x  5, slope is 4 perpendicular slope is 1/4 point is (1,5) , slope is 1/4 y = mx + b {slopeintercept form} 5 = (1/4)(1) + b {substituted point (x,y) and slope into slopeintercept form} 5 = (1/4) + b {multiplied} b = 19/4 {added 1/4 to each side} y = mx + b {slopeintercept form} y = (1/4)x  (19/4) {substituted slope and yintercept into slopeintercept form} Ask Algebra House Comments are closed.

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