Find the equation of the line perpendicular to y = 4x - 5 and passing through (1,-5) .
Perpendicular lines have slopes which are negative reciprocals.
Slope-intercept form is y = mx + b m is the slope b is the y-intercept In y = 4x - 5, slope is 4 perpendicular slope is -1/4 point is (1,-5) , slope is -1/4 y = mx + b {slope-intercept form} -5 = (-1/4)(1) + b {substituted point (x,y) and slope into slope-intercept form} -5 = (-1/4) + b {multiplied} b = -19/4 {added 1/4 to each side} y = mx + b {slope-intercept form} y = (-1/4)x - (19/4) {substituted slope and y-intercept into slope-intercept form} Ask Algebra House Comments are closed.
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