Factoring Algebraic Expression

Algebra help (factoring expression)?
 y²x² – 16y² – 6x² + 96
I took out two from the integers and was left with (8y² – 3x² + 48)
What happens now. What’s going on with y²x² 

You can't factor out a common factor, there is none. Cross out your (8y² – 3x² + 48)

This is a little more confusing:
y²x² – 16y– 6x² + 96

= (y²x² – 16y²) + (- 6x² + 96) {group pairs of terms}
= y²(x² - 16) - 6(x² - 16) {factor out y2(left) and -6(right)}
= (y² - 6)(x² - 16) {factor x2 - 16 out of the previous two}
= (y² - 6)(x + 4)(x - 4) {this is your answer completely simplified}

in the previous line x² - 16 was a difference of two squares
factoring into (x + 4)(x - 4)........you can check the final answer
by multiplying it all back together to get the original expression

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