Algebra help (factoring expression)? y2x2 – 16y2 – 6x2 + 96 I took out two from the integers and was left with (8y2 – 3x2 + 48) What happens now. What’s going on with y2x2 You can't factor out a common factor, there is none. Cross out your (8y2 – 3x2 + 48)
This is a little more confusing: y2x2 – 16y2 – 6x2 + 96 = (y 2x2 – 16y2) + ( 6x2 + 96) {group pairs of terms} = y 2 (x2  16)  6(x2  16) {factor out y2(left) and 6(right)} = (y2  6)(x2  16) {factor x2  16 out of the previous two} = (y2  6)(x + 4)(x  4) {this is your answer completely simplified} in the previous line x2  16 was a difference of two squares factoring into (x + 4)(x  4)........you can check the final answer by multiplying it all back together to get the original expression  Algebra House
2 Comments
Rachael
6/8/2011 05:48:51 am
How do you factor these out completely?
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6/8/2011 06:49:59 am
4x² + 36
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