Algebra help (factoring expression)?
y²x² – 16y² – 6x² + 96 I took out two from the integers and was left with (8y² – 3x² + 48) What happens now. What’s going on with y²x²
You can't factor out a common factor, there is none. Cross out your (8y² – 3x² + 48)
This is a little more confusing: y²x² – 16y– 6x² + 96 = (y²x² – 16y²) + (- 6x² + 96) {group pairs of terms} = y²(x² - 16) - 6(x² - 16) {factor out y2(left) and -6(right)} = (y² - 6)(x² - 16) {factor x2 - 16 out of the previous two} = (y² - 6)(x + 4)(x - 4) {this is your answer completely simplified} in the previous line x² - 16 was a difference of two squares factoring into (x + 4)(x - 4)........you can check the final answer by multiplying it all back together to get the original expression Ask Algebra House
2 Comments
Rachael
6/8/2011 05:48:51 am
How do you factor these out completely?
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6/8/2011 06:49:59 am
4x² + 36
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