Algebra help (factoring expression)?
y²x² – 16y² – 6x² + 96 I took out two from the integers and was left with (8y² – 3x² + 48) What happens now. What’s going on with y²x²
You can't factor out a common factor, there is none. Cross out your (8y² – 3x² + 48)
This is a little more confusing: y²x² – 16y– 6x² + 96 = (y²x² – 16y²) + ( 6x² + 96) {group pairs of terms} = y²(x²  16)  6(x²  16) {factor out y2(left) and 6(right)} = (y²  6)(x²  16) {factor x2  16 out of the previous two} = (y²  6)(x + 4)(x  4) {this is your answer completely simplified} in the previous line x²  16 was a difference of two squares factoring into (x + 4)(x  4)........you can check the final answer by multiplying it all back together to get the original expression Ask Algebra House
2 Comments
Rachael
6/8/2011 05:48:51 am
How do you factor these out completely?
Reply
6/8/2011 06:49:59 am
4x² + 36
Reply
Your comment will be posted after it is approved.
Leave a Reply. 
Latest Videos
Categories
All
Archives
January 2022
