y2x2 – 16y2 – 6x2 + 96

I took out two from the integers and was left with (8y2 – 3x2 + 48)

What happens now. What’s going on with y2x2

This is a little more confusing:

y2x2 – 16y2 – 6x2 + 96

= (y 2x2 – 16y2) + (- 6x2 + 96) {group pairs of terms}

= y 2 (x2 - 16) - 6(x2 - 16) {factor out y2(left) and -6(right)}

= (y2 - 6)(x2 - 16) {factor x2 - 16 out of the previous two}

= (y2 - 6)(x + 4)(x - 4) {this is your answer completely simplified}

in the previous line x2 - 16 was a difference of two squares

factoring into (x + 4)(x - 4)........you can check the final answer

by multiplying it all back together to get the original expression

- Algebra House