Art leaves his house at 10 o'clock traveling at 50 mph. Jennifer leaves her house at 10:30 traveling at 60 mph. At what time will Jennifer catch up to Art?

**Distance = rate x time**

**Art's distance**d = rt {distance = rate x time}

rate = 50

time = t

**d = 50t**

__Jennifer's distance__d = rt {distance = rate x time}

rate = 60

time = t - 0.5 {left 1/2 hour later than Art}

**d =**60(t - 0.5) =

**60t - 30**{used distributive property}

50t = 60t - 30 {when Jennifer catches up with Art, the distances will be equal}

-10t = -30 {subtracted 60t from each side}

t = 3 {divided each side by -10}

**In 3 hours**, Jennifer will catch up with Art

**- Algebra House**