Art leaves his house at 10 o'clock traveling at 50 mph. Jennifer leaves her house at 10:30 traveling at 60 mph. At what time will Jennifer catch up to Art? Distance = rate x time Art's distance d = rt {distance = rate x time} rate = 50 time = t d = 50t Jennifer's distance d = rt {distance = rate x time} rate = 60 time = t  0.5 {left 1/2 hour later than Art} d = 60(t  0.5) = 60t  30 {used distributive property} 50t = 60t  30 {when Jennifer catches up with Art, the distances will be equal} 10t = 30 {subtracted 60t from each side} t = 3 {divided each side by 10} In 3 hours, Jennifer will catch up with Art  Algebra House
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